sin平方的(10)+cos平方的(40)+sin10*cos40
=(1-cos20)/2+cos40(cos40+cos80)
=(1-cos20)/2+cos40*2cos60cos20
=(1-cos20)/2+cos40*cos20
=(1-cos20)/2+(cos60+cos20)/2
=1/2+cos60/2
=1/2+1/4
=3/4
sin平方的(10)+cos平方的(40)+sin10*cos40
=(1-cos20)/2+cos40(cos40+cos80)
=(1-cos20)/2+cos40*2cos60cos20
=(1-cos20)/2+cos40*cos20
=(1-cos20)/2+(cos60+cos20)/2
=1/2+cos60/2
=1/2+1/4
=3/4