Question

已知-3≤log1/2 x≤-1,f(x)=[log2(x*4^m)]*[log2(4/x)]

Answer 1

(1)由-3≤log1/2 x≤-1,1≤log2x≤3

f(x)=log2(x*4^m)]*[log2(4/x)]=(log2(4^m)+log2x)(log24-log2x)=(2m+log2x)(2-log2x)=-(log2x)^2+(2-2m)log2x+4m

对称轴log2x=1-m

当1