Question

逻辑函数Y=A+(B+C')'(A+B'+C)(A+B+C),希望马上可以有人给答案

Answer 1

Y=A+(B+C')'(A+B'+C)(A+B+C)

=A+(B'C)(A+B'+C)(A+B+C)

=A+(B'C)[(A+C)+(A+C)B'+(A+C)B+B'B]

=A+(B'C)(A+C)

=A+AB'C+B'C

=A+B'C