Question

（x-2）分之3-（x-1）分之4=（x-4）分之1-（x-3）分之2怎么解

Answer 1

3/(x-2)+2/(x-3)=4/(x-1)+1/(x-4),移项通分得（5x-13)/(x^2-5x+6)=(5x-17)/(x^2-5x+4),交换内项得（5x-13)/(5x-17)=(x^2-5x+6) /(x^2-5x+4),{写不下过程} 化简为 1+4/(5x-17)=1+2/(x^2-5x+4),可得x=5或x=5/2