Question

若|a+b-1|+(a-b-3)^2=0,求3a^2(a^3b^2-2a)-4a(-a^2(b)^2

Answer 1

|a+b-1|+(a-b-3)^2=0

因为：|a+b-1|>=0,(a-b-3)^2>=0

所以：

a+b-1=0,a-b-3=0

a=2,b=-1

3a^2(a^3b^2-2a)-4a(-a^2(b)^2

=3a^3(a^2b^2-2)-4a^3*a^2b^2

=-a^3(a^2b^2+2)

=-48