令 x=(√2)sint,则 dx=(√2)costdt
[0,1]∫x²dx/√(2-x²)
=[0,π/4]∫2sin²t(√2)costdt/√(2-2sin²t)
=[0,π/4]∫(1-cos2t)dt
=(t-½sin2t)|[0,π/4]
=π/4-½
令 x=(√2)sint,则 dx=(√2)costdt
[0,1]∫x²dx/√(2-x²)
=[0,π/4]∫2sin²t(√2)costdt/√(2-2sin²t)
=[0,π/4]∫(1-cos2t)dt
=(t-½sin2t)|[0,π/4]
=π/4-½