设圆圆心为点c(x,y),题中过m点的弦为BD,则AB垂直于MC,三角形CMA为直角三角形,边长分别为
BC=5,BM=2√3,CM=√[(x+1)^2+(y-3)^2]
可知:=(x+1)^2+(y-3)^2 + (2√3)^2 =25
又圆过A点,则 (x+2)^2 + (y-4)^2 =25
解方程组:x1=1,y1=0
x2=2,y2=1
圆方差:(x-1)^2 + y^2 =25
(x-2)^2 + (y-1)^2=25
设圆圆心为点c(x,y),题中过m点的弦为BD,则AB垂直于MC,三角形CMA为直角三角形,边长分别为
BC=5,BM=2√3,CM=√[(x+1)^2+(y-3)^2]
可知:=(x+1)^2+(y-3)^2 + (2√3)^2 =25
又圆过A点,则 (x+2)^2 + (y-4)^2 =25
解方程组:x1=1,y1=0
x2=2,y2=1
圆方差:(x-1)^2 + y^2 =25
(x-2)^2 + (y-1)^2=25